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mathswithmish
GCSE VS A-Level Maths | Day 5: Binomial Expansion (Year 12 intro) - Get a head start this summer ✨ #gcsemaths #alevelmaths #binomialexpansion #expandingbrackets
Maths with Mish 📝(@mathswithmish). It's A Vibe! - The JoVell Experience and AaRon Toney. GCSE VS A-Level Maths | Day 5: Binomial Expansion(Year 12 intro) - Get a head start this summer #gcsemaths #alevelmaths #binomialexpansion #expandingbrackets #year12maths
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editing my friend giving charity to the israeli community Graham's number is an immense number that arose as an upper bound on the answer of a problem in the mathematical field of Ramsey theory. It is much larger than many other large numbers introduced as effective bounds in mathematics, such as Skewes's bound, which in turn is much larger than a googolplex. Graham's number is so large that the observable universe is far too small to contain its ordinary digital representation, assuming that ea
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editing my friend giving charity to the israeli community Graham's number is an immense number that arose as an upper bound on the answer of a problem in the mathematical field of Ramsey theory. It is much larger than many other large numbers introduced as effective bounds in mathematics, such as Skewes's bound, which in turn is much larger than a googolplex. Graham's number is so large that the observable universe is far too small to contain its ordinary digital representation, assuming that ea
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My favorite actor Hello @Amiosfolihi Graham's number is an immense number that arose as an upper bound on the answer of a problem in the mathematical field of Ramsey theory. It is much larger than many other large numbers introduced as effective bounds in mathematics, such as Skewes's bound, which in turn is much larger than a googolplex. Graham's number is so large that the observable universe is far too small to contain its ordinary digital representation, assuming that each digit occupies one
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AQA FM: Binomial Expansion Question: Find the first 3 terms in the expansion, in ascending powers of x, of: (3 - x/9)^6 Give the terms in their simplest form. Key exam skill: Use binomial coefficients and take the first 3 terms only. For power 6, the first three coefficients are: 1, 6, 15 So: (3 - x/9)^6 First term: 3^6 = 729 Second term: 6 x 3^5 x (-x/9) = -162x Third term: 15 x 3^4 x (x^2/81) = 15x^2 Final answer: 729 - 162x 15x^2 Save this for revision. Follow for more AQA Level 2 Further Mat
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